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43142021161 is a prime number
BaseRepresentation
bin101000001011011101…
…110000000000101001
311010100122022202020121
4220023131300000221
51201323324134121
631452535123241
73055046062231
oct501335600051
9133318282217
1043142021161
1117329601048
128440213521
1340b7001095
1421339c2cc1
1511c7781141
hexa0b770029

43142021161 has 2 divisors, whose sum is σ = 43142021162. Its totient is φ = 43142021160.

The previous prime is 43142021159. The next prime is 43142021177. The reversal of 43142021161 is 16112024134.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 22386144400 + 20755876761 = 149620^2 + 144069^2 .

It is a cyclic number.

It is not a de Polignac number, because 43142021161 - 21 = 43142021159 is a prime.

It is a super-2 number, since 2×431420211612 (a number of 22 digits) contains 22 as substring.

Together with 43142021159, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (43142021761) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21571010580 + 21571010581.

It is an arithmetic number, because the mean of its divisors is an integer number (21571010581).

Almost surely, 243142021161 is an apocalyptic number.

It is an amenable number.

43142021161 is a deficient number, since it is larger than the sum of its proper divisors (1).

43142021161 is an equidigital number, since it uses as much as digits as its factorization.

43142021161 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 43142021161 its reverse (16112024134), we get a palindrome (59254045295).

The spelling of 43142021161 in words is "forty-three billion, one hundred forty-two million, twenty-one thousand, one hundred sixty-one".