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43142425103 is a prime number
BaseRepresentation
bin101000001011011111…
…010010101000001111
311010100200002021100102
4220023133102220033
51201323430100403
631452551521315
73055052364011
oct501337225017
9133320067312
1043142425103
1117329857588
12844038923b
1340b7112bbb
142133a8a1b1
1511c7810b88
hexa0b7d2a0f

43142425103 has 2 divisors, whose sum is σ = 43142425104. Its totient is φ = 43142425102.

The previous prime is 43142424989. The next prime is 43142425141. The reversal of 43142425103 is 30152424134.

43142425103 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 43142425103 - 28 = 43142424847 is a prime.

It is a super-2 number, since 2×431424251032 (a number of 22 digits) contains 22 as substring.

It is a Sophie Germain prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (43142425153) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21571212551 + 21571212552.

It is an arithmetic number, because the mean of its divisors is an integer number (21571212552).

Almost surely, 243142425103 is an apocalyptic number.

43142425103 is a deficient number, since it is larger than the sum of its proper divisors (1).

43142425103 is an equidigital number, since it uses as much as digits as its factorization.

43142425103 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 11520, while the sum is 29.

Adding to 43142425103 its reverse (30152424134), we get a palindrome (73294849237).

The spelling of 43142425103 in words is "forty-three billion, one hundred forty-two million, four hundred twenty-five thousand, one hundred three".