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432014502013 is a prime number
BaseRepresentation
bin1100100100101100001…
…00100010100001111101
31112022002211111120121121
412102112010202201331
524034231203031023
6530244214030541
743132502451403
oct6222604424175
91468084446547
10432014502013
11157241a18626
126b888948451
133197b187563
1416ca3d9d473
15b3872ebd5d
hex649612287d

432014502013 has 2 divisors, whose sum is σ = 432014502014. Its totient is φ = 432014502012.

The previous prime is 432014501999. The next prime is 432014502043. The reversal of 432014502013 is 310205410234.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 327050165689 + 104964336324 = 571883^2 + 323982^2 .

It is a cyclic number.

It is not a de Polignac number, because 432014502013 - 213 = 432014493821 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (432014502043) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 216007251006 + 216007251007.

It is an arithmetic number, because the mean of its divisors is an integer number (216007251007).

Almost surely, 2432014502013 is an apocalyptic number.

It is an amenable number.

432014502013 is a deficient number, since it is larger than the sum of its proper divisors (1).

432014502013 is an equidigital number, since it uses as much as digits as its factorization.

432014502013 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2880, while the sum is 25.

Adding to 432014502013 its reverse (310205410234), we get a palindrome (742219912247).

The spelling of 432014502013 in words is "four hundred thirty-two billion, fourteen million, five hundred two thousand, thirteen".