Base | Representation |
---|---|
bin | 1100100100110000011… |
… | …00101110111011110001 |
3 | 1112022012022200110002021 |
4 | 12102120030232323301 |
5 | 24034314323020101 |
6 | 530251531151441 |
7 | 43133415100114 |
oct | 6223014567361 |
9 | 1468168613067 |
10 | 432050204401 |
11 | 157260093332 |
12 | 6b8988a5581 |
13 | 319856a7c2a |
14 | 16ca8a1457b |
15 | b38a5005a1 |
hex | 649832eef1 |
432050204401 has 2 divisors, whose sum is σ = 432050204402. Its totient is φ = 432050204400.
The previous prime is 432050204393. The next prime is 432050204471. The reversal of 432050204401 is 104402050234.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 364840160400 + 67210044001 = 604020^2 + 259249^2 .
It is a cyclic number.
It is not a de Polignac number, because 432050204401 - 23 = 432050204393 is a prime.
It is not a weakly prime, because it can be changed into another prime (432050204471) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 216025102200 + 216025102201.
It is an arithmetic number, because the mean of its divisors is an integer number (216025102201).
Almost surely, 2432050204401 is an apocalyptic number.
It is an amenable number.
432050204401 is a deficient number, since it is larger than the sum of its proper divisors (1).
432050204401 is an equidigital number, since it uses as much as digits as its factorization.
432050204401 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3840, while the sum is 25.
Adding to 432050204401 its reverse (104402050234), we get a palindrome (536452254635).
The spelling of 432050204401 in words is "four hundred thirty-two billion, fifty million, two hundred four thousand, four hundred one".
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