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43214913611983 is a prime number
BaseRepresentation
bin10011101001101110000011…
…00100110010100011001111
312200000022020122001221212101
421310313001210302203033
521131013120341040413
6231524353544215531
712050113562624131
oct1164670144624317
9180008218057771
1043214913611983
111285138413a403
124a1b40b16a5a7
131b161c20a69b9
14a9588202b051
154ee1bbd32edd
hex274dc19328cf

43214913611983 has 2 divisors, whose sum is σ = 43214913611984. Its totient is φ = 43214913611982.

The previous prime is 43214913611953. The next prime is 43214913612001. The reversal of 43214913611983 is 38911631941234.

It is a happy number.

43214913611983 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 43214913611983 - 25 = 43214913611951 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (43214913611923) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21607456805991 + 21607456805992.

It is an arithmetic number, because the mean of its divisors is an integer number (21607456805992).

Almost surely, 243214913611983 is an apocalyptic number.

43214913611983 is a deficient number, since it is larger than the sum of its proper divisors (1).

43214913611983 is an equidigital number, since it uses as much as digits as its factorization.

43214913611983 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 3359232, while the sum is 55.

The spelling of 43214913611983 in words is "forty-three trillion, two hundred fourteen billion, nine hundred thirteen million, six hundred eleven thousand, nine hundred eighty-three".