Base | Representation |
---|---|
bin | 111110111011010100100… |
… | …110101100011011101101 |
3 | 120022101210011220111212021 |
4 | 332323110212230123231 |
5 | 1031322133311404122 |
6 | 13110320254310141 |
7 | 624264166431361 |
oct | 76732446543355 |
9 | 16271704814767 |
10 | 4324304013037 |
11 | 1417a21976658 |
12 | 59a0b47b8351 |
13 | 254a1abc7c38 |
14 | 10d4242172a1 |
15 | 777421ad1c7 |
hex | 3eed49ac6ed |
4324304013037 has 2 divisors, whose sum is σ = 4324304013038. Its totient is φ = 4324304013036.
The previous prime is 4324304013023. The next prime is 4324304013131. The reversal of 4324304013037 is 7303104034234.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 3341927672836 + 982376340201 = 1828094^2 + 991149^2 .
It is a cyclic number.
It is not a de Polignac number, because 4324304013037 - 235 = 4289944274669 is a prime.
It is a super-3 number, since 3×43243040130373 (a number of 39 digits) contains 333 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 4324304012993 and 4324304013011.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (4324304013737) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2162152006518 + 2162152006519.
It is an arithmetic number, because the mean of its divisors is an integer number (2162152006519).
Almost surely, 24324304013037 is an apocalyptic number.
It is an amenable number.
4324304013037 is a deficient number, since it is larger than the sum of its proper divisors (1).
4324304013037 is an equidigital number, since it uses as much as digits as its factorization.
4324304013037 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 72576, while the sum is 34.
The spelling of 4324304013037 in words is "four trillion, three hundred twenty-four billion, three hundred four million, thirteen thousand, thirty-seven".
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