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4325401340233 is a prime number
BaseRepresentation
bin111110111100010110000…
…000101010100101001001
3120022111121122201111210021
4332330112000222211021
51031331410220341413
613111021214020441
7624333322523131
oct76742600524511
916274548644707
104325401340233
111418435325836
1259a3601a7721
13254b6435117c
1410d4c9c5bac1
15777a86b718d
hex3ef1602a949

4325401340233 has 2 divisors, whose sum is σ = 4325401340234. Its totient is φ = 4325401340232.

The previous prime is 4325401340231. The next prime is 4325401340287. The reversal of 4325401340233 is 3320431045234.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 2752403767369 + 1572997572864 = 1659037^2 + 1254192^2 .

It is a cyclic number.

It is not a de Polignac number, because 4325401340233 - 21 = 4325401340231 is a prime.

Together with 4325401340231, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (4325401340231) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2162700670116 + 2162700670117.

It is an arithmetic number, because the mean of its divisors is an integer number (2162700670117).

Almost surely, 24325401340233 is an apocalyptic number.

It is an amenable number.

4325401340233 is a deficient number, since it is larger than the sum of its proper divisors (1).

4325401340233 is an equidigital number, since it uses as much as digits as its factorization.

4325401340233 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 103680, while the sum is 34.

Adding to 4325401340233 its reverse (3320431045234), we get a palindrome (7645832385467).

The spelling of 4325401340233 in words is "four trillion, three hundred twenty-five billion, four hundred one million, three hundred forty thousand, two hundred thirty-three".