Base | Representation |
---|---|
bin | 111111000001100101000… |
… | …001111100000010000101 |
3 | 120100001010101001201000221 |
4 | 333001211001330002011 |
5 | 1031424413120304341 |
6 | 13113351041104341 |
7 | 624622522635361 |
oct | 77014501740205 |
9 | 16301111051027 |
10 | 4331022041221 |
11 | 141a85a03a667 |
12 | 59b46a6280b1 |
13 | 25554b975b45 |
14 | 10d8a05342a1 |
15 | 779d6d79ed1 |
hex | 3f06507c085 |
4331022041221 has 2 divisors, whose sum is σ = 4331022041222. Its totient is φ = 4331022041220.
The previous prime is 4331022041209. The next prime is 4331022041261. The reversal of 4331022041221 is 1221402201334.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 3649589952100 + 681432089121 = 1910390^2 + 825489^2 .
It is a cyclic number.
It is not a de Polignac number, because 4331022041221 - 219 = 4331021516933 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (4331022041261) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2165511020610 + 2165511020611.
It is an arithmetic number, because the mean of its divisors is an integer number (2165511020611).
Almost surely, 24331022041221 is an apocalyptic number.
It is an amenable number.
4331022041221 is a deficient number, since it is larger than the sum of its proper divisors (1).
4331022041221 is an equidigital number, since it uses as much as digits as its factorization.
4331022041221 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2304, while the sum is 25.
Adding to 4331022041221 its reverse (1221402201334), we get a palindrome (5552424242555).
The spelling of 4331022041221 in words is "four trillion, three hundred thirty-one billion, twenty-two million, forty-one thousand, two hundred twenty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.078 sec. • engine limits •