43311126041 has 2 divisors, whose sum is σ = 43311126042. Its totient is φ = 43311126040.

The previous prime is 43311126029. The next prime is 43311126043. The reversal of 43311126041 is 14062111334.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 32412601225 + 10898524816 = 180035^2 + 104396^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-43311126041 is a prime.

Together with 43311126043, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 43311126041.

It is not a weakly prime, because it can be changed into another prime (43311126043) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21655563020 + 21655563021.

It is an arithmetic number, because the mean of its divisors is an integer number (21655563021).

Almost surely, 2^43311126041 is an apocalyptic number.

It is an amenable number.

43311126041 is a deficient number, since it is larger than the sum of its proper divisors (1).

43311126041 is an equidigital number, since it uses as much as digits as its factorization.

43311126041 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1728, while the sum is 26.

Adding to 43311126041 its reverse (14062111334), we get a palindrome (57373237375).

The spelling of 43311126041 in words is "forty-three billion, three hundred eleven million, one hundred twenty-six thousand, forty-one".