4331215114040 has 32 divisors (see below), whose sum is σ = 9854731026000. Its totient is φ = 1713019908864.

The previous prime is 4331215114027. The next prime is 4331215114049. The reversal of 4331215114040 is 404115121334.

4331215114040 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a junction number, because it is equal to n+sod(n) for n = 4331215113994 and 4331215114012.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (4331215114049) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 608313170 + ... + 608320289.

Almost surely, 2^{4331215114040} is an apocalyptic number.

4331215114040 is a gapful number since it is divisible by the number (40) formed by its first and last digit.

It is an amenable number.

4331215114040 is an abundant number, since it is smaller than the sum of its proper divisors (5523515911960).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

4331215114040 is a wasteful number, since it uses less digits than its factorization.

4331215114040 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1216633559 (or 1216633555 counting only the distinct ones).

The product of its (nonzero) digits is 5760, while the sum is 29.

The spelling of 4331215114040 in words is "four trillion, three hundred thirty-one billion, two hundred fifteen million, one hundred fourteen thousand, forty".