4331231104037 has 2 divisors, whose sum is σ = 4331231104038. Its totient is φ = 4331231104036.

The previous prime is 4331231103911. The next prime is 4331231104043. The reversal of 4331231104037 is 7304011321334.

4331231104037 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 3597948874276 + 733282229761 = 1896826^2 + 856319^2 .

It is a cyclic number.

It is not a de Polignac number, because 4331231104037 - 2⁸ = 4331231103781 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 4331231103994 and 4331231104012.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (4331231164037) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2165615552018 + 2165615552019.

It is an arithmetic number, because the mean of its divisors is an integer number (2165615552019).

Almost surely, 2^{4331231104037} is an apocalyptic number.

It is an amenable number.

4331231104037 is a deficient number, since it is larger than the sum of its proper divisors (1).

4331231104037 is an equidigital number, since it uses as much as digits as its factorization.

4331231104037 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 18144, while the sum is 32.

The spelling of 4331231104037 in words is "four trillion, three hundred thirty-one billion, two hundred thirty-one million, one hundred four thousand, thirty-seven".