Base | Representation |
---|---|
bin | 111111000001110001011… |
… | …111100011000110101001 |
3 | 120100001122221111111221201 |
4 | 333001301133203012221 |
5 | 1031430330132130100 |
6 | 13113423510404201 |
7 | 624630642105622 |
oct | 77016137430651 |
9 | 16301587444851 |
10 | 4331231130025 |
11 | 141a957070128 |
12 | 59b508660661 |
13 | 255583093027 |
14 | 10d8c0200a49 |
15 | 779ea3cc36a |
hex | 3f0717e31a9 |
4331231130025 has 48 divisors (see below), whose sum is σ = 5425971287040. Its totient is φ = 3429571622400.
The previous prime is 4331231129989. The next prime is 4331231130041. The reversal of 4331231130025 is 5200311321334.
It is not a de Polignac number, because 4331231130025 - 215 = 4331231097257 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 4331231129975 and 4331231130002.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 827041707 + ... + 827046943.
It is an arithmetic number, because the mean of its divisors is an integer number (113041068480).
Almost surely, 24331231130025 is an apocalyptic number.
It is an amenable number.
4331231130025 is a deficient number, since it is larger than the sum of its proper divisors (1094740157015).
4331231130025 is a wasteful number, since it uses less digits than its factorization.
4331231130025 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6274 (or 6269 counting only the distinct ones).
The product of its (nonzero) digits is 6480, while the sum is 28.
Adding to 4331231130025 its reverse (5200311321334), we get a palindrome (9531542451359).
The spelling of 4331231130025 in words is "four trillion, three hundred thirty-one billion, two hundred thirty-one million, one hundred thirty thousand, twenty-five".
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