Base | Representation |
---|---|
bin | 111111000001110001011… |
… | …111100011000110111010 |
3 | 120100001122221111111222100 |
4 | 333001301133203012322 |
5 | 1031430330132130132 |
6 | 13113423510404230 |
7 | 624630642105645 |
oct | 77016137430672 |
9 | 16301587444870 |
10 | 4331231130042 |
11 | 141a957070143 |
12 | 59b508660676 |
13 | 25558309303b |
14 | 10d8c0200a5c |
15 | 779ea3cc37c |
hex | 3f0717e31ba |
4331231130042 has 24 divisors (see below), whose sum is σ = 9384411306816. Its totient is φ = 1443731834376.
The previous prime is 4331231130041. The next prime is 4331231130067. The reversal of 4331231130042 is 2400311321334.
It is a happy number.
4331231130042 is a `hidden beast` number, since 4 + 3 + 3 + 1 + 2 + 311 + 300 + 42 = 666.
It is a junction number, because it is equal to n+sod(n) for n = 4331231129988 and 4331231130015.
It is not an unprimeable number, because it can be changed into a prime (4331231130041) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 1417713 + ... + 3266859.
It is an arithmetic number, because the mean of its divisors is an integer number (391017137784).
Almost surely, 24331231130042 is an apocalyptic number.
4331231130042 is an abundant number, since it is smaller than the sum of its proper divisors (5053180176774).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
4331231130042 is a wasteful number, since it uses less digits than its factorization.
4331231130042 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1979282 (or 1979279 counting only the distinct ones).
The product of its (nonzero) digits is 5184, while the sum is 27.
Adding to 4331231130042 its reverse (2400311321334), we get a palindrome (6731542451376).
The spelling of 4331231130042 in words is "four trillion, three hundred thirty-one billion, two hundred thirty-one million, one hundred thirty thousand, forty-two".
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