Base | Representation |
---|---|
bin | 1100100110110001010… |
… | …01001101101010011101 |
3 | 1112101222200011111020210 |
4 | 12103120221031222131 |
5 | 24044023120142000 |
6 | 530551113203033 |
7 | 43202254154166 |
oct | 6233051155235 |
9 | 1471880144223 |
10 | 433131412125 |
11 | 157765432735 |
12 | 6bb3aa00479 |
13 | 31ac86a9109 |
14 | 16d6c46076d |
15 | b4003c3350 |
hex | 64d8a4da9d |
433131412125 has 64 divisors (see below), whose sum is σ = 733591572480. Its totient is φ = 226888251200.
The previous prime is 433131412117. The next prime is 433131412127. The reversal of 433131412125 is 521214131334.
It is not a de Polignac number, because 433131412125 - 23 = 433131412117 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 433131412092 and 433131412101.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (433131412127) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 27050872 + ... + 27066878.
It is an arithmetic number, because the mean of its divisors is an integer number (11462368320).
Almost surely, 2433131412125 is an apocalyptic number.
It is an amenable number.
433131412125 is a deficient number, since it is larger than the sum of its proper divisors (300460160355).
433131412125 is a wasteful number, since it uses less digits than its factorization.
433131412125 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 17307 (or 17297 counting only the distinct ones).
The product of its digits is 8640, while the sum is 30.
Adding to 433131412125 its reverse (521214131334), we get a palindrome (954345543459).
The spelling of 433131412125 in words is "four hundred thirty-three billion, one hundred thirty-one million, four hundred twelve thousand, one hundred twenty-five".
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