4331400003941 has 2 divisors, whose sum is σ = 4331400003942. Its totient is φ = 4331400003940.

The previous prime is 4331400003919. The next prime is 4331400004003. The reversal of 4331400003941 is 1493000041334.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 2251110136900 + 2080289867041 = 1500370^2 + 1442321^2 .

It is a cyclic number.

It is not a de Polignac number, because 4331400003941 - 2¹⁴ = 4331399987557 is a prime.

It is a super-2 number, since 2×4331400003941² (a number of 26 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 4331400003898 and 4331400003907.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (4331400203941) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2165700001970 + 2165700001971.

It is an arithmetic number, because the mean of its divisors is an integer number (2165700001971).

Almost surely, 2^{4331400003941} is an apocalyptic number.

It is an amenable number.

4331400003941 is a deficient number, since it is larger than the sum of its proper divisors (1).

4331400003941 is an equidigital number, since it uses as much as digits as its factorization.

4331400003941 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 15552, while the sum is 32.

The spelling of 4331400003941 in words is "four trillion, three hundred thirty-one billion, four hundred million, three thousand, nine hundred forty-one".