Base | Representation |
---|---|
bin | 1100100110110010010… |
… | …01111110011010010000 |
3 | 1112102000021022211011001 |
4 | 12103121021332122100 |
5 | 24044032320003100 |
6 | 530552021231344 |
7 | 43202420153662 |
oct | 6233111763220 |
9 | 1472007284131 |
10 | 433140000400 |
11 | 15776a269188 |
12 | 6bb41862554 |
13 | 31aca3c5233 |
14 | 16d6d658532 |
15 | b40101cd6a |
hex | 64d927e690 |
433140000400 has 30 divisors (see below), whose sum is σ = 1040618851922. Its totient is φ = 173256000000.
The previous prime is 433140000347. The next prime is 433140000421. The reversal of 433140000400 is 4000041334.
It can be written as a sum of positive squares in 3 ways, for example, as 123220656784 + 309919343616 = 351028^2 + 556704^2 .
It is a super-2 number, since 2×4331400004002 (a number of 24 digits) contains 22 as substring.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 541424601 + ... + 541425400.
Almost surely, 2433140000400 is an apocalyptic number.
433140000400 is a gapful number since it is divisible by the number (40) formed by its first and last digit.
It is an amenable number.
433140000400 is an abundant number, since it is smaller than the sum of its proper divisors (607478851522).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
433140000400 is a wasteful number, since it uses less digits than its factorization.
433140000400 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1082850019 (or 1082850008 counting only the distinct ones).
The product of its (nonzero) digits is 576, while the sum is 19.
Adding to 433140000400 its reverse (4000041334), we get a palindrome (437140041734).
The spelling of 433140000400 in words is "four hundred thirty-three billion, one hundred forty million, four hundred", and thus it is an aban number.
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