Base | Representation |
---|---|
bin | 111111000001111100001… |
… | …010011001010001111100 |
3 | 120100002010102022212102202 |
4 | 333001330022121101330 |
5 | 1031431211443243030 |
6 | 13113453343211032 |
7 | 624635244445535 |
oct | 77017412312174 |
9 | 16302112285382 |
10 | 4331410134140 |
11 | 141aa39112611 |
12 | 59b5585a6a78 |
13 | 2555b11a881b |
14 | 10d8d9cb968c |
15 | 77a0ae8a745 |
hex | 3f07c29947c |
4331410134140 has 48 divisors (see below), whose sum is σ = 9665292125664. Its totient is φ = 1624845465600.
The previous prime is 4331410134119. The next prime is 4331410134169. The reversal of 4331410134140 is 414310141334.
It is a super-2 number, since 2×43314101341402 (a number of 26 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 22572506 + ... + 22763585.
It is an arithmetic number, because the mean of its divisors is an integer number (201360252618).
Almost surely, 24331410134140 is an apocalyptic number.
It is an amenable number.
4331410134140 is an abundant number, since it is smaller than the sum of its proper divisors (5333881991524).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
4331410134140 is a wasteful number, since it uses less digits than its factorization.
4331410134140 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 45336398 (or 45336396 counting only the distinct ones).
The product of its (nonzero) digits is 6912, while the sum is 29.
Adding to 4331410134140 its reverse (414310141334), we get a palindrome (4745720275474).
The spelling of 4331410134140 in words is "four trillion, three hundred thirty-one billion, four hundred ten million, one hundred thirty-four thousand, one hundred forty".
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