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4333141140221 is a prime number
BaseRepresentation
bin111111000011100011010…
…101101010001011111101
3120100020121001112002101002
4333003203111222023331
51031443233112441341
613114341220500045
7625026163656515
oct77034325521375
916306531462332
104333141140221
111420747233053
1259b96024a625
132557c89bcc8a
1410da21b52845
1577aace1629b
hex3f0e356a2fd

4333141140221 has 2 divisors, whose sum is σ = 4333141140222. Its totient is φ = 4333141140220.

The previous prime is 4333141140197. The next prime is 4333141140241. The reversal of 4333141140221 is 1220411413334.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2209723872196 + 2123417268025 = 1486514^2 + 1457195^2 .

It is a cyclic number.

It is not a de Polignac number, because 4333141140221 - 214 = 4333141123837 is a prime.

It is a super-2 number, since 2×43331411402212 (a number of 26 digits) contains 22 as substring.

It is a Sophie Germain prime.

It is a Curzon number.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (4333141140241) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2166570570110 + 2166570570111.

It is an arithmetic number, because the mean of its divisors is an integer number (2166570570111).

Almost surely, 24333141140221 is an apocalyptic number.

It is an amenable number.

4333141140221 is a deficient number, since it is larger than the sum of its proper divisors (1).

4333141140221 is an equidigital number, since it uses as much as digits as its factorization.

4333141140221 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6912, while the sum is 29.

Adding to 4333141140221 its reverse (1220411413334), we get a palindrome (5553552553555).

The spelling of 4333141140221 in words is "four trillion, three hundred thirty-three billion, one hundred forty-one million, one hundred forty thousand, two hundred twenty-one".