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433420422013 is a prime number
BaseRepresentation
bin1100100111010011101…
…11101100101101111101
31112102201210222201021201
412103221313230231331
524100121112001023
6531035515455501
743212363541465
oct6235167545575
91472653881251
10433420422013
111578a3590087
126bbbb757591
1331b43529797
1416d989b2ba5
15b41a960bad
hex64e9decb7d

433420422013 has 2 divisors, whose sum is σ = 433420422014. Its totient is φ = 433420422012.

The previous prime is 433420422011. The next prime is 433420422101. The reversal of 433420422013 is 310224024334.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 382940667684 + 50479754329 = 618822^2 + 224677^2 .

It is a cyclic number.

It is not a de Polignac number, because 433420422013 - 21 = 433420422011 is a prime.

Together with 433420422011, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (433420422011) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 216710211006 + 216710211007.

It is an arithmetic number, because the mean of its divisors is an integer number (216710211007).

Almost surely, 2433420422013 is an apocalyptic number.

It is an amenable number.

433420422013 is a deficient number, since it is larger than the sum of its proper divisors (1).

433420422013 is an equidigital number, since it uses as much as digits as its factorization.

433420422013 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 13824, while the sum is 28.

Adding to 433420422013 its reverse (310224024334), we get a palindrome (743644446347).

The spelling of 433420422013 in words is "four hundred thirty-three billion, four hundred twenty million, four hundred twenty-two thousand, thirteen".