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4335144112361 is a prime number
BaseRepresentation
bin111111000101011010101…
…110011001000011101001
3120100102202122110121121102
4333011122232121003221
51032011333343043421
613115312051251145
7625126624650446
oct77053256310351
916312678417542
104335144112361
11142158491a727
125a021aba9ab5
13255a579680aa
1410db71b829cd
1577b78bb460b
hex3f15ab990e9

4335144112361 has 2 divisors, whose sum is σ = 4335144112362. Its totient is φ = 4335144112360.

The previous prime is 4335144112303. The next prime is 4335144112363. The reversal of 4335144112361 is 1632114415334.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 3374822510761 + 960321601600 = 1837069^2 + 979960^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-4335144112361 is a prime.

Together with 4335144112363, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (4335144112363) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2167572056180 + 2167572056181.

It is an arithmetic number, because the mean of its divisors is an integer number (2167572056181).

Almost surely, 24335144112361 is an apocalyptic number.

It is an amenable number.

4335144112361 is a deficient number, since it is larger than the sum of its proper divisors (1).

4335144112361 is an equidigital number, since it uses as much as digits as its factorization.

4335144112361 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 103680, while the sum is 38.

Adding to 4335144112361 its reverse (1632114415334), we get a palindrome (5967258527695).

The spelling of 4335144112361 in words is "four trillion, three hundred thirty-five billion, one hundred forty-four million, one hundred twelve thousand, three hundred sixty-one".