Search a number
-
+
43354753613 is a prime number
BaseRepresentation
bin101000011000001001…
…010000101001001101
311010220110121200022022
4220120021100221031
51202242304103423
631530014455525
73063241216403
oct503011205115
9133813550268
1043354753613
11174286a0096
12849b5045a5
13411c0c5882
142153d5b473
1511db2a2dc8
hexa18250a4d

43354753613 has 2 divisors, whose sum is σ = 43354753614. Its totient is φ = 43354753612.

The previous prime is 43354753579. The next prime is 43354753657. The reversal of 43354753613 is 31635745334.

It is an a-pointer prime, because the next prime (43354753657) can be obtained adding 43354753613 to its sum of digits (44).

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 36044161609 + 7310592004 = 189853^2 + 85502^2 .

It is a cyclic number.

It is not a de Polignac number, because 43354753613 - 26 = 43354753549 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (43354753313) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21677376806 + 21677376807.

It is an arithmetic number, because the mean of its divisors is an integer number (21677376807).

Almost surely, 243354753613 is an apocalyptic number.

It is an amenable number.

43354753613 is a deficient number, since it is larger than the sum of its proper divisors (1).

43354753613 is an equidigital number, since it uses as much as digits as its factorization.

43354753613 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 1360800, while the sum is 44.

The spelling of 43354753613 in words is "forty-three billion, three hundred fifty-four million, seven hundred fifty-three thousand, six hundred thirteen".