Base | Representation |
---|---|
bin | 111111001001111101011… |
… | …000000000001101110101 |
3 | 120100220100111002100221221 |
4 | 333021331120000031311 |
5 | 1032101330211211201 |
6 | 13121440003310341 |
7 | 625361515556326 |
oct | 77117530001565 |
9 | 16326314070857 |
10 | 4340020413301 |
11 | 1423657419801 |
12 | 5a116007b3b1 |
13 | 256353ca6171 |
14 | 1100b564444d |
15 | 77d61d344a1 |
hex | 3f27d600375 |
4340020413301 has 2 divisors, whose sum is σ = 4340020413302. Its totient is φ = 4340020413300.
The previous prime is 4340020413217. The next prime is 4340020413347. The reversal of 4340020413301 is 1033140200434.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 3948427314225 + 391593099076 = 1987065^2 + 625774^2 .
It is a cyclic number.
It is not a de Polignac number, because 4340020413301 - 27 = 4340020413173 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (4340020413371) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2170010206650 + 2170010206651.
It is an arithmetic number, because the mean of its divisors is an integer number (2170010206651).
Almost surely, 24340020413301 is an apocalyptic number.
It is an amenable number.
4340020413301 is a deficient number, since it is larger than the sum of its proper divisors (1).
4340020413301 is an equidigital number, since it uses as much as digits as its factorization.
4340020413301 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3456, while the sum is 25.
Adding to 4340020413301 its reverse (1033140200434), we get a palindrome (5373160613735).
The spelling of 4340020413301 in words is "four trillion, three hundred forty billion, twenty million, four hundred thirteen thousand, three hundred one".
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