Base | Representation |
---|---|
bin | 111111001010001111110… |
… | …110001000001011010001 |
3 | 120100221011002012020202021 |
4 | 333022033312020023101 |
5 | 1032102444024100423 |
6 | 13121530433251441 |
7 | 625402300554403 |
oct | 77121766101321 |
9 | 16327132166667 |
10 | 4340330300113 |
11 | 14237a6336305 |
12 | 5a1227a03b81 |
13 | 2563a3256142 |
14 | 11010486cb73 |
15 | 77d7e14795d |
hex | 3f28fd882d1 |
4340330300113 has 2 divisors, whose sum is σ = 4340330300114. Its totient is φ = 4340330300112.
The previous prime is 4340330300083. The next prime is 4340330300183. The reversal of 4340330300113 is 3110030330434.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 3634273266129 + 706057033984 = 1906377^2 + 840272^2 .
It is a cyclic number.
It is not a de Polignac number, because 4340330300113 - 217 = 4340330169041 is a prime.
It is a super-2 number, since 2×43403303001132 (a number of 26 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (4340330300183) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2170165150056 + 2170165150057.
It is an arithmetic number, because the mean of its divisors is an integer number (2170165150057).
Almost surely, 24340330300113 is an apocalyptic number.
It is an amenable number.
4340330300113 is a deficient number, since it is larger than the sum of its proper divisors (1).
4340330300113 is an equidigital number, since it uses as much as digits as its factorization.
4340330300113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3888, while the sum is 25.
Adding to 4340330300113 its reverse (3110030330434), we get a palindrome (7450360630547).
The spelling of 4340330300113 in words is "four trillion, three hundred forty billion, three hundred thirty million, three hundred thousand, one hundred thirteen".
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