Base | Representation |
---|---|
bin | 110001010110001000010110… |
… | …0100010010001011010101111 |
3 | 2002220211210021200212222000002 |
4 | 1202230100230202101122233 |
5 | 423342434142340144003 |
6 | 4135051514343454515 |
7 | 160266042103311434 |
oct | 14254205442213257 |
9 | 2086753250788002 |
10 | 434050142115503 |
11 | 1163356a46188a1 |
12 | 408219aa45743b |
13 | 158269a2ac3654 |
14 | 79281d3499b8b |
15 | 352a990e7aa88 |
hex | 18ac42c8916af |
434050142115503 has 2 divisors, whose sum is σ = 434050142115504. Its totient is φ = 434050142115502.
The previous prime is 434050142115479. The next prime is 434050142115539. The reversal of 434050142115503 is 305511241050434.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 434050142115503 - 26 = 434050142115439 is a prime.
It is a super-2 number, since 2×4340501421155032 (a number of 30 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (434050142115203) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 217025071057751 + 217025071057752.
It is an arithmetic number, because the mean of its divisors is an integer number (217025071057752).
Almost surely, 2434050142115503 is an apocalyptic number.
434050142115503 is a deficient number, since it is larger than the sum of its proper divisors (1).
434050142115503 is an equidigital number, since it uses as much as digits as its factorization.
434050142115503 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 144000, while the sum is 38.
Adding to 434050142115503 its reverse (305511241050434), we get a palindrome (739561383165937).
The spelling of 434050142115503 in words is "four hundred thirty-four trillion, fifty billion, one hundred forty-two million, one hundred fifteen thousand, five hundred three".
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