Base | Representation |
---|---|
bin | 110001010110001010101101… |
… | …1110011111001011011110111 |
3 | 2002220212021102022002002002202 |
4 | 1202230111123303321123313 |
5 | 423343030102414413221 |
6 | 4135054115303455115 |
7 | 160266312145506302 |
oct | 14254253363713367 |
9 | 2086767368062082 |
10 | 434055230232311 |
11 | 116337875740306 |
12 | 4082298a45749b |
13 | 15827303c94c5c |
14 | 7928557137b39 |
15 | 352ab8c9dad0b |
hex | 18ac55bcf96f7 |
434055230232311 has 2 divisors, whose sum is σ = 434055230232312. Its totient is φ = 434055230232310.
The previous prime is 434055230232269. The next prime is 434055230232347. The reversal of 434055230232311 is 113232032550434.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-434055230232311 is a prime.
It is a super-3 number, since 3×4340552302323113 (a number of 45 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (434055230232391) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 217027615116155 + 217027615116156.
It is an arithmetic number, because the mean of its divisors is an integer number (217027615116156).
Almost surely, 2434055230232311 is an apocalyptic number.
434055230232311 is a deficient number, since it is larger than the sum of its proper divisors (1).
434055230232311 is an equidigital number, since it uses as much as digits as its factorization.
434055230232311 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 259200, while the sum is 38.
Adding to 434055230232311 its reverse (113232032550434), we get a palindrome (547287262782745).
The spelling of 434055230232311 in words is "four hundred thirty-four trillion, fifty-five billion, two hundred thirty million, two hundred thirty-two thousand, three hundred eleven".
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