Base | Representation |
---|---|
bin | 111111001010100100100… |
… | …001111111101011101111 |
3 | 120100222001021012220102221 |
4 | 333022210201333223233 |
5 | 1032104201400001413 |
6 | 13122025111500211 |
7 | 625414013440201 |
oct | 77124441775357 |
9 | 16328037186387 |
10 | 4340677343983 |
11 | 1423964221522 |
12 | 5a1304087667 |
13 | 25642a115946 |
14 | 1101389aa771 |
15 | 77d9e84a68d |
hex | 3f2a487faef |
4340677343983 has 2 divisors, whose sum is σ = 4340677343984. Its totient is φ = 4340677343982.
The previous prime is 4340677343927. The next prime is 4340677344053. The reversal of 4340677343983 is 3893437760434.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-4340677343983 is a prime.
It is a super-2 number, since 2×43406773439832 (a number of 26 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (4340677343923) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2170338671991 + 2170338671992.
It is an arithmetic number, because the mean of its divisors is an integer number (2170338671992).
Almost surely, 24340677343983 is an apocalyptic number.
4340677343983 is a deficient number, since it is larger than the sum of its proper divisors (1).
4340677343983 is an equidigital number, since it uses as much as digits as its factorization.
4340677343983 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 109734912, while the sum is 61.
The spelling of 4340677343983 in words is "four trillion, three hundred forty billion, six hundred seventy-seven million, three hundred forty-three thousand, nine hundred eighty-three".
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