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4340677344053 is a prime number
BaseRepresentation
bin111111001010100100100…
…001111111101100110101
3120100222001021012220112112
4333022210201333230311
51032104201400002203
613122025111500405
7625414013440331
oct77124441775465
916328037186475
104340677344053
111423964221586
125a1304087705
1325642a11599b
141101389aa7c1
1577d9e84a6d8
hex3f2a487fb35

4340677344053 has 2 divisors, whose sum is σ = 4340677344054. Its totient is φ = 4340677344052.

The previous prime is 4340677343983. The next prime is 4340677344067. The reversal of 4340677344053 is 3504437760434.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 3497472243409 + 843205100644 = 1870153^2 + 918262^2 .

It is a cyclic number.

It is not a de Polignac number, because 4340677344053 - 216 = 4340677278517 is a prime.

It is a super-2 number, since 2×43406773440532 (a number of 26 digits) contains 22 as substring.

It is a Sophie Germain prime.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 4340677343992 and 4340677344010.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (4340677344253) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2170338672026 + 2170338672027.

It is an arithmetic number, because the mean of its divisors is an integer number (2170338672027).

Almost surely, 24340677344053 is an apocalyptic number.

It is an amenable number.

4340677344053 is a deficient number, since it is larger than the sum of its proper divisors (1).

4340677344053 is an equidigital number, since it uses as much as digits as its factorization.

4340677344053 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 10160640, while the sum is 50.

The spelling of 4340677344053 in words is "four trillion, three hundred forty billion, six hundred seventy-seven million, three hundred forty-four thousand, fifty-three".