Base | Representation |
---|---|
bin | 1100101000100111011… |
… | …01100111110000110111 |
3 | 1112111112201221002002021 |
4 | 12110103231213300313 |
5 | 24103040320021401 |
6 | 531233314054011 |
7 | 43235646466561 |
oct | 6242355476067 |
9 | 1474481832067 |
10 | 434122423351 |
11 | 158123877081 |
12 | 7017687a307 |
13 | 31c25ab9aa6 |
14 | 17023d0c331 |
15 | b45c3cb2a1 |
hex | 6513b67c37 |
434122423351 has 2 divisors, whose sum is σ = 434122423352. Its totient is φ = 434122423350.
The previous prime is 434122423337. The next prime is 434122423367. The reversal of 434122423351 is 153324221434.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 434122423351 - 235 = 399762684983 is a prime.
It is a super-2 number, since 2×4341224233512 (a number of 24 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (434122423051) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 217061211675 + 217061211676.
It is an arithmetic number, because the mean of its divisors is an integer number (217061211676).
Almost surely, 2434122423351 is an apocalyptic number.
434122423351 is a deficient number, since it is larger than the sum of its proper divisors (1).
434122423351 is an equidigital number, since it uses as much as digits as its factorization.
434122423351 is an evil number, because the sum of its binary digits is even.
The product of its digits is 69120, while the sum is 34.
Adding to 434122423351 its reverse (153324221434), we get a palindrome (587446644785).
The spelling of 434122423351 in words is "four hundred thirty-four billion, one hundred twenty-two million, four hundred twenty-three thousand, three hundred fifty-one".
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