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4341314113 is a prime number
BaseRepresentation
bin1000000101100001…
…10011001001000001
3102012112221121101121
410002300303021001
532342334022423
61554441232241
7212403363313
oct40260631101
912175847347
104341314113
111928616604
12a11a92681
13542556226
142d27dd7b3
151a61e545d
hex102c33241

4341314113 has 2 divisors, whose sum is σ = 4341314114. Its totient is φ = 4341314112.

The previous prime is 4341314071. The next prime is 4341314119. The reversal of 4341314113 is 3114131434.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2441051649 + 1900262464 = 49407^2 + 43592^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-4341314113 is a prime.

It is not a weakly prime, because it can be changed into another prime (4341314119) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2170657056 + 2170657057.

It is an arithmetic number, because the mean of its divisors is an integer number (2170657057).

Almost surely, 24341314113 is an apocalyptic number.

It is an amenable number.

4341314113 is a deficient number, since it is larger than the sum of its proper divisors (1).

4341314113 is an equidigital number, since it uses as much as digits as its factorization.

4341314113 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 1728, while the sum is 25.

The square root of 4341314113 is about 65888.6493487308. The cubic root of 4341314113 is about 1631.3246678426.

Adding to 4341314113 its reverse (3114131434), we get a palindrome (7455445547).

It can be divided in two parts, 434131 and 4113, that added together give a square (438244 = 6622).

The spelling of 4341314113 in words is "four billion, three hundred forty-one million, three hundred fourteen thousand, one hundred thirteen".