Base | Representation |
---|---|
bin | 110001010110101110001110… |
… | …1111111001101011111011111 |
3 | 2002221010120021211122202200112 |
4 | 1202231130131333031133133 |
5 | 423400302304110000413 |
6 | 4135153131533320235 |
7 | 160304652223435232 |
oct | 14255343577153737 |
9 | 2087116254582615 |
10 | 434131502421983 |
11 | 116367155372303 |
12 | 4083571593607b |
13 | 1583156a9b9a32 |
14 | 792c110b73419 |
15 | 352cb53a9d2a8 |
hex | 18ad71dfcd7df |
434131502421983 has 2 divisors, whose sum is σ = 434131502421984. Its totient is φ = 434131502421982.
The previous prime is 434131502421919. The next prime is 434131502422039. The reversal of 434131502421983 is 389124205131434.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 434131502421983 - 26 = 434131502421919 is a prime.
It is a super-2 number, since 2×4341315024219832 (a number of 30 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (434131502421283) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 217065751210991 + 217065751210992.
It is an arithmetic number, because the mean of its divisors is an integer number (217065751210992).
Almost surely, 2434131502421983 is an apocalyptic number.
434131502421983 is a deficient number, since it is larger than the sum of its proper divisors (1).
434131502421983 is an equidigital number, since it uses as much as digits as its factorization.
434131502421983 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2488320, while the sum is 50.
The spelling of 434131502421983 in words is "four hundred thirty-four trillion, one hundred thirty-one billion, five hundred two million, four hundred twenty-one thousand, nine hundred eighty-three".
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