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434131502422039 is a prime number
BaseRepresentation
bin110001010110101110001110…
…1111111001101100000010111
32002221010120021211122202202121
41202231130131333031200113
5423400302304110001124
64135153131533320411
7160304652223435342
oct14255343577154027
92087116254582677
10434131502422039
11116367155372354
1240835715936107
131583156a9b9a76
14792c110b73459
15352cb53a9d2e4
hex18ad71dfcd817

434131502422039 has 2 divisors, whose sum is σ = 434131502422040. Its totient is φ = 434131502422038.

The previous prime is 434131502421983. The next prime is 434131502422061. The reversal of 434131502422039 is 930224205131434.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 434131502422039 - 221 = 434131500324887 is a prime.

It is a super-2 number, since 2×4341315024220392 (a number of 30 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 434131502421986 and 434131502422004.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (434131502420039) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 217065751211019 + 217065751211020.

It is an arithmetic number, because the mean of its divisors is an integer number (217065751211020).

Almost surely, 2434131502422039 is an apocalyptic number.

434131502422039 is a deficient number, since it is larger than the sum of its proper divisors (1).

434131502422039 is an equidigital number, since it uses as much as digits as its factorization.

434131502422039 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 622080, while the sum is 43.

The spelling of 434131502422039 in words is "four hundred thirty-four trillion, one hundred thirty-one billion, five hundred two million, four hundred twenty-two thousand, thirty-nine".