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43413234001037 is a prime number
BaseRepresentation
bin10011101111011111011100…
…11001000010010010001101
312200201021010220212120021222
421313233232121002102031
521142240300401013122
6232155433034333125
712100334260255205
oct1167575631022215
9180637126776258
1043413234001037
11129184a38a3a8a
124a5193828a1a5
131b2bb09437b34
14aa12d7013405
15504427aceb42
hex277bee64248d

43413234001037 has 2 divisors, whose sum is σ = 43413234001038. Its totient is φ = 43413234001036.

The previous prime is 43413234001003. The next prime is 43413234001043. The reversal of 43413234001037 is 73010043231434.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 41041307509801 + 2371926491236 = 6406349^2 + 1540106^2 .

It is a cyclic number.

It is not a de Polignac number, because 43413234001037 - 26 = 43413234000973 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 43413234000988 and 43413234001006.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (43413294001037) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21706617000518 + 21706617000519.

It is an arithmetic number, because the mean of its divisors is an integer number (21706617000519).

Almost surely, 243413234001037 is an apocalyptic number.

It is an amenable number.

43413234001037 is a deficient number, since it is larger than the sum of its proper divisors (1).

43413234001037 is an equidigital number, since it uses as much as digits as its factorization.

43413234001037 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 72576, while the sum is 35.

The spelling of 43413234001037 in words is "forty-three trillion, four hundred thirteen billion, two hundred thirty-four million, one thousand, thirty-seven".