Base | Representation |
---|---|
bin | 111111001011001111101… |
… | …111101000101011011101 |
3 | 120101000220210102112002112 |
4 | 333023033233220223131 |
5 | 1032112142444340221 |
6 | 13122225051003405 |
7 | 625440666006323 |
oct | 77131757505335 |
9 | 16330823375075 |
10 | 4341402340061 |
11 | 14241a6493836 |
12 | 5a1486a39565 |
13 | 2565143974c7 |
14 | 1101a6dadd13 |
15 | 77de330915b |
hex | 3f2cfbe8add |
4341402340061 has 2 divisors, whose sum is σ = 4341402340062. Its totient is φ = 4341402340060.
The previous prime is 4341402339977. The next prime is 4341402340091. The reversal of 4341402340061 is 1600432041434.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 3935640984025 + 405761356036 = 1983845^2 + 636994^2 .
It is a cyclic number.
It is not a de Polignac number, because 4341402340061 - 218 = 4341402077917 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (4341402340091) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2170701170030 + 2170701170031.
It is an arithmetic number, because the mean of its divisors is an integer number (2170701170031).
Almost surely, 24341402340061 is an apocalyptic number.
It is an amenable number.
4341402340061 is a deficient number, since it is larger than the sum of its proper divisors (1).
4341402340061 is an equidigital number, since it uses as much as digits as its factorization.
4341402340061 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 27648, while the sum is 32.
Adding to 4341402340061 its reverse (1600432041434), we get a palindrome (5941834381495).
The spelling of 4341402340061 in words is "four trillion, three hundred forty-one billion, four hundred two million, three hundred forty thousand, sixty-one".
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