Base | Representation |
---|---|
bin | 111111001011010000010… |
… | …001001101111100000111 |
3 | 120101000221101222210001021 |
4 | 333023100101031330013 |
5 | 1032112202223042211 |
6 | 13122230003412011 |
7 | 625441133563165 |
oct | 77132021157407 |
9 | 16330841883037 |
10 | 4341411143431 |
11 | 142420045694a |
12 | 5a1489984007 |
13 | 25651615a4bb |
14 | 1101a8222235 |
15 | 77de3e97771 |
hex | 3f2d044df07 |
4341411143431 has 2 divisors, whose sum is σ = 4341411143432. Its totient is φ = 4341411143430.
The previous prime is 4341411143383. The next prime is 4341411143491. The reversal of 4341411143431 is 1343411141434.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-4341411143431 is a prime.
It is a super-2 number, since 2×43414111434312 (a number of 26 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (4341411143491) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2170705571715 + 2170705571716.
It is an arithmetic number, because the mean of its divisors is an integer number (2170705571716).
Almost surely, 24341411143431 is an apocalyptic number.
4341411143431 is a deficient number, since it is larger than the sum of its proper divisors (1).
4341411143431 is an equidigital number, since it uses as much as digits as its factorization.
4341411143431 is an evil number, because the sum of its binary digits is even.
The product of its digits is 27648, while the sum is 34.
Adding to 4341411143431 its reverse (1343411141434), we get a palindrome (5684822284865).
The spelling of 4341411143431 in words is "four trillion, three hundred forty-one billion, four hundred eleven million, one hundred forty-three thousand, four hundred thirty-one".
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