Base | Representation |
---|---|
bin | 1100101001001000101… |
… | …01100000000101011111 |
3 | 1112112021011201010220221 |
4 | 12110210111200011133 |
5 | 24104123214004434 |
6 | 531321115422211 |
7 | 43245604144354 |
oct | 6244425400537 |
9 | 1475234633827 |
10 | 434401313119 |
11 | 158257242094 |
12 | 70234154967 |
13 | 31c6b806017 |
14 | 1704cd8862b |
15 | b476b1a2b4 |
hex | 652456015f |
434401313119 has 2 divisors, whose sum is σ = 434401313120. Its totient is φ = 434401313118.
The previous prime is 434401313113. The next prime is 434401313161. The reversal of 434401313119 is 911313104434.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 434401313119 - 225 = 434367758687 is a prime.
It is a super-2 number, since 2×4344013131192 (a number of 24 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (434401313113) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 217200656559 + 217200656560.
It is an arithmetic number, because the mean of its divisors is an integer number (217200656560).
Almost surely, 2434401313119 is an apocalyptic number.
434401313119 is a deficient number, since it is larger than the sum of its proper divisors (1).
434401313119 is an equidigital number, since it uses as much as digits as its factorization.
434401313119 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 15552, while the sum is 34.
The spelling of 434401313119 in words is "four hundred thirty-four billion, four hundred one million, three hundred thirteen thousand, one hundred nineteen".
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