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43520131141 is a prime number
BaseRepresentation
bin101000100010000000…
…001000000001000101
311011022222210201121221
4220202000020001011
51203112123144031
631554243240341
73100320003544
oct504200100105
9134288721557
1043520131141
1117502a85733
1285269790b1
134147449bb6
14216bcca15b
1511eaa6da11
hexa22008045

43520131141 has 2 divisors, whose sum is σ = 43520131142. Its totient is φ = 43520131140.

The previous prime is 43520131129. The next prime is 43520131147. The reversal of 43520131141 is 14113102534.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 35500212225 + 8019918916 = 188415^2 + 89554^2 .

It is a cyclic number.

It is not a de Polignac number, because 43520131141 - 219 = 43519606853 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (43520131147) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21760065570 + 21760065571.

It is an arithmetic number, because the mean of its divisors is an integer number (21760065571).

Almost surely, 243520131141 is an apocalyptic number.

It is an amenable number.

43520131141 is a deficient number, since it is larger than the sum of its proper divisors (1).

43520131141 is an equidigital number, since it uses as much as digits as its factorization.

43520131141 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1440, while the sum is 25.

Adding to 43520131141 its reverse (14113102534), we get a palindrome (57633233675).

The spelling of 43520131141 in words is "forty-three billion, five hundred twenty million, one hundred thirty-one thousand, one hundred forty-one".