Base | Representation |
---|---|
bin | 111111011000000000110… |
… | …111001110010000000111 |
3 | 120102100022012021120120022 |
4 | 333120000313032100013 |
5 | 1032323231444030224 |
6 | 13132413245525355 |
7 | 626434501243544 |
oct | 77300067162007 |
9 | 16370265246508 |
10 | 4355111314439 |
11 | 1429aa0888126 |
12 | 5a4071b7385b |
13 | 2578ba5cb372 |
14 | 110b0796bbcb |
15 | 78446b0265e |
hex | 3f600dce407 |
4355111314439 has 2 divisors, whose sum is σ = 4355111314440. Its totient is φ = 4355111314438.
The previous prime is 4355111314423. The next prime is 4355111314441. The reversal of 4355111314439 is 9344131115534.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 4355111314439 - 24 = 4355111314423 is a prime.
It is a super-2 number, since 2×43551113144392 (a number of 26 digits) contains 22 as substring.
Together with 4355111314441, it forms a pair of twin primes.
It is a Chen prime.
It is a self number, because there is not a number n which added to its sum of digits gives 4355111314439.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (4355111314459) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2177555657219 + 2177555657220.
It is an arithmetic number, because the mean of its divisors is an integer number (2177555657220).
Almost surely, 24355111314439 is an apocalyptic number.
4355111314439 is a deficient number, since it is larger than the sum of its proper divisors (1).
4355111314439 is an equidigital number, since it uses as much as digits as its factorization.
4355111314439 is an evil number, because the sum of its binary digits is even.
The product of its digits is 388800, while the sum is 44.
The spelling of 4355111314439 in words is "four trillion, three hundred fifty-five billion, one hundred eleven million, three hundred fourteen thousand, four hundred thirty-nine".
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