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43628312040791 is a prime number
BaseRepresentation
bin10011110101110000000100…
…00010101001010101010111
312201110211022002011000220012
421322320002002221111113
521204301240340301131
6232442323031230435
712122020146401612
oct1172700202512527
9181424262130805
1043628312040791
11129a0732839665
124a8756151841b
131b461944c810a
14aab89b831179
15509d14b3152b
hex27ae020a9557

43628312040791 has 2 divisors, whose sum is σ = 43628312040792. Its totient is φ = 43628312040790.

The previous prime is 43628312040787. The next prime is 43628312040793. The reversal of 43628312040791 is 19704021382634.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 43628312040791 - 22 = 43628312040787 is a prime.

It is a super-2 number, since 2×436283120407912 (a number of 28 digits) contains 22 as substring.

Together with 43628312040793, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (43628312040793) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21814156020395 + 21814156020396.

It is an arithmetic number, because the mean of its divisors is an integer number (21814156020396).

Almost surely, 243628312040791 is an apocalyptic number.

43628312040791 is a deficient number, since it is larger than the sum of its proper divisors (1).

43628312040791 is an equidigital number, since it uses as much as digits as its factorization.

43628312040791 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1741824, while the sum is 50.

The spelling of 43628312040791 in words is "forty-three trillion, six hundred twenty-eight billion, three hundred twelve million, forty thousand, seven hundred ninety-one".