Base | Representation |
---|---|
bin | 101000111000111010… |
… | …010001000010101101 |
3 | 11012022210000020002102 |
4 | 220320322101002231 |
5 | 1204404021034323 |
6 | 32100333104445 |
7 | 3112664563541 |
oct | 507072210255 |
9 | 135283006072 |
10 | 43904471213 |
11 | 1768aa25059 |
12 | 8613628125 |
13 | 41a8c67665 |
14 | 21a6d75a21 |
15 | 121e68c328 |
hex | a38e910ad |
43904471213 has 2 divisors, whose sum is σ = 43904471214. Its totient is φ = 43904471212.
The previous prime is 43904471129. The next prime is 43904471243. The reversal of 43904471213 is 31217440934.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 43832865769 + 71605444 = 209363^2 + 8462^2 .
It is a cyclic number.
It is not a de Polignac number, because 43904471213 - 210 = 43904470189 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (43904471243) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21952235606 + 21952235607.
It is an arithmetic number, because the mean of its divisors is an integer number (21952235607).
Almost surely, 243904471213 is an apocalyptic number.
It is an amenable number.
43904471213 is a deficient number, since it is larger than the sum of its proper divisors (1).
43904471213 is an equidigital number, since it uses as much as digits as its factorization.
43904471213 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 72576, while the sum is 38.
The spelling of 43904471213 in words is "forty-three billion, nine hundred four million, four hundred seventy-one thousand, two hundred thirteen".
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