Base | Representation |
---|---|
bin | 10100000000110000110011… |
… | …00011100001001101001111 |
3 | 12202210222220001110112011202 |
4 | 22000120121203201031033 |
5 | 21232001121344000041 |
6 | 233332214315340115 |
7 | 12161243102150141 |
oct | 1200303143411517 |
9 | 182728801415152 |
10 | 44006663656271 |
11 | 13027137423288 |
12 | 4b2895275163b |
13 | 1b72a6cab4a74 |
14 | ac1d10820c91 |
15 | 514aaac03a9b |
hex | 2806198e134f |
44006663656271 has 2 divisors, whose sum is σ = 44006663656272. Its totient is φ = 44006663656270.
The previous prime is 44006663656243. The next prime is 44006663656273. The reversal of 44006663656271 is 17265636660044.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 44006663656271 - 222 = 44006659461967 is a prime.
Together with 44006663656273, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (44006663656273) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 22003331828135 + 22003331828136.
It is an arithmetic number, because the mean of its divisors is an integer number (22003331828136).
Almost surely, 244006663656271 is an apocalyptic number.
44006663656271 is a deficient number, since it is larger than the sum of its proper divisors (1).
44006663656271 is an equidigital number, since it uses as much as digits as its factorization.
44006663656271 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 26127360, while the sum is 56.
The spelling of 44006663656271 in words is "forty-four trillion, six billion, six hundred sixty-three million, six hundred fifty-six thousand, two hundred seventy-one".
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