Base | Representation |
---|---|
bin | 110010000010010011010011… |
… | …1111111100000001100111011 |
3 | 2010201100011020101002222221212 |
4 | 1210010212213333200030323 |
5 | 430141420303023240201 |
6 | 4200020444103353335 |
7 | 161463456503310434 |
oct | 14404464777401473 |
9 | 2121304211088855 |
10 | 440121002165051 |
11 | 1182662a5878269 |
12 | 4144249515284b |
13 | 15b7730381733c |
14 | 7a97d821bc48b |
15 | 35d3855cadabb |
hex | 19049a7fe033b |
440121002165051 has 2 divisors, whose sum is σ = 440121002165052. Its totient is φ = 440121002165050.
The previous prime is 440121002165011. The next prime is 440121002165057. The reversal of 440121002165051 is 150561200121044.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-440121002165051 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 440121002164999 and 440121002165017.
It is not a weakly prime, because it can be changed into another prime (440121002165057) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 220060501082525 + 220060501082526.
It is an arithmetic number, because the mean of its divisors is an integer number (220060501082526).
Almost surely, 2440121002165051 is an apocalyptic number.
440121002165051 is a deficient number, since it is larger than the sum of its proper divisors (1).
440121002165051 is an equidigital number, since it uses as much as digits as its factorization.
440121002165051 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 9600, while the sum is 32.
Adding to 440121002165051 its reverse (150561200121044), we get a palindrome (590682202286095).
The spelling of 440121002165051 in words is "four hundred forty trillion, one hundred twenty-one billion, two million, one hundred sixty-five thousand, fifty-one".
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