440131111330541 has 2 divisors, whose sum is σ = 440131111330542. Its totient is φ = 440131111330540.

The previous prime is 440131111330531. The next prime is 440131111330637. The reversal of 440131111330541 is 145033111131044.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 317468508981316 + 122662602349225 = 17817646^2 + 11075315^2 .

It is a cyclic number.

It is not a de Polignac number, because 440131111330541 - 2²⁶ = 440131044221677 is a prime.

It is a super-2 number, since 2×440131111330541² (a number of 30 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 440131111330498 and 440131111330507.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (440131111330531) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 220065555665270 + 220065555665271.

It is an arithmetic number, because the mean of its divisors is an integer number (220065555665271).

Almost surely, 2^{440131111330541} is an apocalyptic number.

It is an amenable number.

440131111330541 is a deficient number, since it is larger than the sum of its proper divisors (1).

440131111330541 is an equidigital number, since it uses as much as digits as its factorization.

440131111330541 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 8640, while the sum is 32.

Adding to 440131111330541 its reverse (145033111131044), we get a palindrome (585164222461585).

The spelling of 440131111330541 in words is "four hundred forty trillion, one hundred thirty-one billion, one hundred eleven million, three hundred thirty thousand, five hundred forty-one".