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44013873068063 is a prime number
BaseRepresentation
bin10100000000111110001110…
…10001001111100000011111
312202211200111111020120221022
422000133013101033200133
521232110403001134223
6233335405534154355
712161616543143333
oct1200370721174037
9182750444216838
1044013873068063
111302a1a69a9048
124b2a2250529bb
131b7364b5bbbc2
14ac23d60cd7c3
15514d7dad5ac8
hex2807c744f81f

44013873068063 has 2 divisors, whose sum is σ = 44013873068064. Its totient is φ = 44013873068062.

The previous prime is 44013873068057. The next prime is 44013873068107. The reversal of 44013873068063 is 36086037831044.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 44013873068063 - 26 = 44013873067999 is a prime.

It is a super-3 number, since 3×440138730680633 (a number of 42 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a junction number, because it is equal to n+sod(n) for n = 44013873067996 and 44013873068014.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (44013873058063) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 22006936534031 + 22006936534032.

It is an arithmetic number, because the mean of its divisors is an integer number (22006936534032).

Almost surely, 244013873068063 is an apocalyptic number.

44013873068063 is a deficient number, since it is larger than the sum of its proper divisors (1).

44013873068063 is an equidigital number, since it uses as much as digits as its factorization.

44013873068063 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6967296, while the sum is 53.

The spelling of 44013873068063 in words is "forty-four trillion, thirteen billion, eight hundred seventy-three million, sixty-eight thousand, sixty-three".