Base | Representation |
---|---|
bin | 10100000000111110111011… |
… | …10011110001110001000001 |
3 | 12202211201110211210200220211 |
4 | 22000133131303301301001 |
5 | 21232112141303020113 |
6 | 233335511243234121 |
7 | 12161632114321243 |
oct | 1200373563616101 |
9 | 182751424720824 |
10 | 44014251220033 |
11 | 1302a380401236 |
12 | 4b2a30b818941 |
13 | 1b736aba50b73 |
14 | ac2430408093 |
15 | 514da1dd0b3d |
hex | 2807ddcf1c41 |
44014251220033 has 2 divisors, whose sum is σ = 44014251220034. Its totient is φ = 44014251220032.
The previous prime is 44014251220019. The next prime is 44014251220087. The reversal of 44014251220033 is 33002215241044.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 43880330353729 + 133920866304 = 6624223^2 + 365952^2 .
It is a cyclic number.
It is not a de Polignac number, because 44014251220033 - 241 = 41815227964481 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 44014251219977 and 44014251220004.
It is not a weakly prime, because it can be changed into another prime (44014251260033) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 22007125610016 + 22007125610017.
It is an arithmetic number, because the mean of its divisors is an integer number (22007125610017).
Almost surely, 244014251220033 is an apocalyptic number.
It is an amenable number.
44014251220033 is a deficient number, since it is larger than the sum of its proper divisors (1).
44014251220033 is an equidigital number, since it uses as much as digits as its factorization.
44014251220033 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 23040, while the sum is 31.
Adding to 44014251220033 its reverse (33002215241044), we get a palindrome (77016466461077).
The spelling of 44014251220033 in words is "forty-four trillion, fourteen billion, two hundred fifty-one million, two hundred twenty thousand, thirty-three".
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