Base | Representation |
---|---|
bin | 10100000000111110111011… |
… | …10011110001110001000010 |
3 | 12202211201110211210200220212 |
4 | 22000133131303301301002 |
5 | 21232112141303020114 |
6 | 233335511243234122 |
7 | 12161632114321244 |
oct | 1200373563616102 |
9 | 182751424720825 |
10 | 44014251220034 |
11 | 1302a380401237 |
12 | 4b2a30b818942 |
13 | 1b736aba50b74 |
14 | ac2430408094 |
15 | 514da1dd0b3e |
hex | 2807ddcf1c42 |
44014251220034 has 4 divisors (see below), whose sum is σ = 66021376830054. Its totient is φ = 22007125610016.
The previous prime is 44014251220033. The next prime is 44014251220087. The reversal of 44014251220034 is 43002215241044.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 37164227485009 + 6850023735025 = 6096247^2 + 2617255^2 .
It is a super-2 number, since 2×440142512200342 (a number of 28 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (44014251220033) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11003562805007 + ... + 11003562805010.
Almost surely, 244014251220034 is an apocalyptic number.
44014251220034 is a deficient number, since it is larger than the sum of its proper divisors (22007125610020).
44014251220034 is a wasteful number, since it uses less digits than its factorization.
44014251220034 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 22007125610019.
The product of its (nonzero) digits is 30720, while the sum is 32.
Adding to 44014251220034 its reverse (43002215241044), we get a palindrome (87016466461078).
The spelling of 44014251220034 in words is "forty-four trillion, fourteen billion, two hundred fifty-one million, two hundred twenty thousand, thirty-four".
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