Base | Representation |
---|---|
bin | 10100000000111110111011… |
… | …10011110001110001110111 |
3 | 12202211201110211210200222211 |
4 | 22000133131303301301313 |
5 | 21232112141303020322 |
6 | 233335511243234251 |
7 | 12161632114321351 |
oct | 1200373563616167 |
9 | 182751424720884 |
10 | 44014251220087 |
11 | 1302a380401285 |
12 | 4b2a30b818987 |
13 | 1b736aba50bb5 |
14 | ac24304080d1 |
15 | 514da1dd0b77 |
hex | 2807ddcf1c77 |
44014251220087 has 2 divisors, whose sum is σ = 44014251220088. Its totient is φ = 44014251220086.
The previous prime is 44014251220033. The next prime is 44014251220139. The reversal of 44014251220087 is 78002215241044.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 44014251220087 - 223 = 44014242831479 is a prime.
It is a super-2 number, since 2×440142512200872 (a number of 28 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (44014251220487) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 22007125610043 + 22007125610044.
It is an arithmetic number, because the mean of its divisors is an integer number (22007125610044).
Almost surely, 244014251220087 is an apocalyptic number.
44014251220087 is a deficient number, since it is larger than the sum of its proper divisors (1).
44014251220087 is an equidigital number, since it uses as much as digits as its factorization.
44014251220087 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 143360, while the sum is 40.
The spelling of 44014251220087 in words is "forty-four trillion, fourteen billion, two hundred fifty-one million, two hundred twenty thousand, eighty-seven".
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