Base | Representation |
---|---|
bin | 100000000011010010110… |
… | …1011011101110111000111 |
3 | 120121010101110112121000221 |
4 | 1000012211223131313013 |
5 | 1034133142001113133 |
6 | 13211403521245211 |
7 | 633155002441243 |
oct | 100064553356707 |
9 | 16533343477027 |
10 | 4405121113543 |
11 | 1449224033407 |
12 | 5b18aa193807 |
13 | 25c52a3bc377 |
14 | 1132cd6cd423 |
15 | 798c2280a2d |
hex | 401a5adddc7 |
4405121113543 has 2 divisors, whose sum is σ = 4405121113544. Its totient is φ = 4405121113542.
The previous prime is 4405121113501. The next prime is 4405121113607. The reversal of 4405121113543 is 3453111215044.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 4405121113543 - 233 = 4396531178951 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 4405121113499 and 4405121113508.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (4405121114543) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2202560556771 + 2202560556772.
It is an arithmetic number, because the mean of its divisors is an integer number (2202560556772).
Almost surely, 24405121113543 is an apocalyptic number.
4405121113543 is a deficient number, since it is larger than the sum of its proper divisors (1).
4405121113543 is an equidigital number, since it uses as much as digits as its factorization.
4405121113543 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 28800, while the sum is 34.
Adding to 4405121113543 its reverse (3453111215044), we get a palindrome (7858232328587).
The spelling of 4405121113543 in words is "four trillion, four hundred five billion, one hundred twenty-one million, one hundred thirteen thousand, five hundred forty-three".
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