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44085394981 is a prime number
BaseRepresentation
bin101001000011101100…
…011011111000100101
311012210101110002211201
4221003230123320211
51210241330114411
632130315002501
73120322450225
oct510354337045
9135711402751
1044085394981
1117773068831
128664139431
1342075a2b44
1421c2dd0085
1512304c93c1
hexa43b1be25

44085394981 has 2 divisors, whose sum is σ = 44085394982. Its totient is φ = 44085394980.

The previous prime is 44085394979. The next prime is 44085394987. The reversal of 44085394981 is 18949358044.

44085394981 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 35131504356 + 8953890625 = 187434^2 + 94625^2 .

It is a cyclic number.

It is not a de Polignac number, because 44085394981 - 21 = 44085394979 is a prime.

It is a super-3 number, since 3×440853949813 (a number of 33 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

Together with 44085394979, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (44085394987) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 22042697490 + 22042697491.

It is an arithmetic number, because the mean of its divisors is an integer number (22042697491).

Almost surely, 244085394981 is an apocalyptic number.

It is an amenable number.

44085394981 is a deficient number, since it is larger than the sum of its proper divisors (1).

44085394981 is an equidigital number, since it uses as much as digits as its factorization.

44085394981 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4976640, while the sum is 55.

The spelling of 44085394981 in words is "forty-four billion, eighty-five million, three hundred ninety-four thousand, nine hundred eighty-one".