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44113311450317 is a prime number
BaseRepresentation
bin10100000011110111011100…
…10000100100010011001101
312210012012011112002210110202
422001323232100210103031
521240223030212402232
6233453213035543245
712202036660352324
oct1201735620442315
9183165145083422
1044113311450317
111306839431144a
124b455568bab25
131b7cb37951145
14ac714a7190bb
1551774d885162
hex281eee4244cd

44113311450317 has 2 divisors, whose sum is σ = 44113311450318. Its totient is φ = 44113311450316.

The previous prime is 44113311450277. The next prime is 44113311450343. The reversal of 44113311450317 is 71305411331144.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 36129488229961 + 7983823220356 = 6010781^2 + 2825566^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-44113311450317 is a prime.

It is a super-2 number, since 2×441133114503172 (a number of 28 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (44113311450017) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 22056655725158 + 22056655725159.

It is an arithmetic number, because the mean of its divisors is an integer number (22056655725159).

Almost surely, 244113311450317 is an apocalyptic number.

It is an amenable number.

44113311450317 is a deficient number, since it is larger than the sum of its proper divisors (1).

44113311450317 is an equidigital number, since it uses as much as digits as its factorization.

44113311450317 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 60480, while the sum is 38.

The spelling of 44113311450317 in words is "forty-four trillion, one hundred thirteen billion, three hundred eleven million, four hundred fifty thousand, three hundred seventeen".