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44131220034 = 23111835336433
BaseRepresentation
bin101001000110011011…
…001111101001000010
311012220120200020222220
4221012123033221002
51210340043020114
632135033111510
73121420116036
oct510633175102
9135816606886
1044131220034
1117796a17880
128677558596
134213c28b65
1421c911c1c6
15123452c0a9
hexa466cfa42

44131220034 has 32 divisors (see below), whose sum is σ = 96294187584. Its totient is φ = 13372001280.

The previous prime is 44131220027. The next prime is 44131220051. The reversal of 44131220034 is 43002213144.

It is a super-2 number, since 2×441312200342 (a number of 22 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 44131219986 and 44131220013.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1193082 + ... + 1229514.

It is an arithmetic number, because the mean of its divisors is an integer number (3009193362).

Almost surely, 244131220034 is an apocalyptic number.

44131220034 is an abundant number, since it is smaller than the sum of its proper divisors (52162967550).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

44131220034 is a wasteful number, since it uses less digits than its factorization.

44131220034 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 54802.

The product of its (nonzero) digits is 2304, while the sum is 24.

Adding to 44131220034 its reverse (43002213144), we get a palindrome (87133433178).

The spelling of 44131220034 in words is "forty-four billion, one hundred thirty-one million, two hundred twenty thousand, thirty-four".

Divisors: 1 2 3 6 11 22 33 66 18353 36433 36706 55059 72866 109299 110118 201883 218598 400763 403766 605649 801526 1202289 1211298 2404578 668654849 1337309698 2005964547 4011929094 7355203339 14710406678 22065610017 44131220034